-(x%5E2-27x)%3Dax%5E2%2Bbx-what-is-the-value-of-b-a.jpeg "(8x^2-15x)-(x^2-27x)=ax^2+bx What Is The Value Of B-a")
Solving for the Value of b-a
We are given the equation: (8x^2-15x)-(x^2-27x) = ax^2 + bx
To find the value of b-a, we need to simplify the equation and identify the coefficients of the x^2 and x terms.
1. Simplify the Equation:
First, distribute the negative sign in the second part of the equation: 8x^2 - 15x - x^2 + 27x = ax^2 + bx
Now combine like terms: 7x^2 + 12x = ax^2 + bx
2. Identify the Coefficients:
By comparing both sides of the equation, we can see:
- a = 7 (coefficient of x^2 on the left side)
- b = 12 (coefficient of x on the left side)
3. Calculate b-a:
Finally, substitute the values we found: b - a = 12 - 7 = 5
Therefore, the value of b-a is 5.